Question

Without actual calculating the cubes , the value of 28^3+(-15)^3+(-13)^3 is

Answer 1

Answer:

16380

Step-by-step explanation:

$a^{3}+b^{3}+c^{3} =(a+b+c)^{3}-3(a+b)(b+c)(c+a)$

a=28,b=-15,c=-13

a+b+c=0

a+b=13,b+c=-28,c+a=15

putting these values in above formula will give

$a^{3} +b^{3} +c^{3}=0-3(13)(-28)(15)= 16380$