Question

without actual calculating the cubes the value of
28^3 + (-15)^3 + (-13)^3 is:​

Answer 1

Answer:

HEY MATE !!

HERE IS UR ANS ⤵️⤵️

28³+ (-15)³+ (-13)³

• 28³+28⁹
• (56)²¹

... HOPE THIS HELPS U ALMOST ...

... THANK Q ...

Answer 2

according to Identity:

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx) \\ if \: x + y + z = 0 \: then \: {x}^{3} + {y}^{3} + {z}^{3} = 3xyz$

the picture above has the proof of that though normally that is not required unless asked in the question

$now \\ 28 + ( - 15) + ( - 13) = 28 - 15 - 13 = 28 - 28 = 0 \\ using \: the \: identity \\ {28}^{3} + {( - 15)}^{3} + {( - 13)}^{3} = 3(28)( - 15)( - 13) = 16380$

hope it helps:)