Question

without actual calculation,find the cubes of:​

Answer 1

Answer:

take the exponent common.... u will get (27-10-17)^3... that is simply 0 qube which is 0

Answer 2

Answer:

13770

Step-by-step explanation:

• a^3 +b^3 +c^3 -3abc =(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

using this formula a=27. b=-17 and c=-10

putting values in above formula

RHS will become zero

take -3abc to right hand side it will become +3abc

therefore;

(27)^3 +(-17)^4 +(-10)^3= 3(27)(-17)(-10)

which is equal to 13770