Without actual division prove that the 4 +23 - 22 + 2x – 3 is exactly divisible by 2 +2x -3
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p(x)= 4+23-22+2x-3
g(x)= 2+2x-3
Using Remainder Theorem,
g(x)=0
2+2x-3=0
2x-1=0
2x=1
x=½.
Putting x= 1/2! in p(x)= 4+23-22+2x-3
p(1/2)= 2+23-22+2×1/2-3
2+1+1-3
3-2
-1.
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