Question

without actually calculating the cubes. evaluate
${14}^{3} + {13}^{3} - {27}^{3}$

Answer 1

Hlo friend.. Cutiepie Here..

Let a = 14

b = 13

c = -27

Now, a + b + c

= 13 + 14 - 27

= 27 - 27

= 0

If a + b + c = 0, then a³ + b³ + c³ = 3abc

${14}^{3} + {13}^{3} - {27}^{3}$


$= 3 \times 14 \times 13 \times - 27$


$= 42 \times - 351$

$= \: - 14,742$


____________________

HOPE IT HELPS YOU..

REGARDS
@sunita

Answer 2

a=14
b=13
c=(-27)
Using identity [if a+b+c=0 then a^3+b^3+c^3=3abc], we get-
14+13+(-27)
14+13-27
=0
Thus, 14^3+13^3-27^3=3(14)(13)(-27)
=(-14742)