Question

Without actually calculating the cubes find the value of (-11)^3+(7)^3+4^3

Answer 1

a^3+b^3+c^3=3abc if a+b+c=0.

Here, a=-11,b=7 and c=4. Therefore, a+b+c=0.

Value is 3*(-11)*7*3=-924. Hope this will help you.

Answer 2

Step-by-step explanation:

using identity = Acube + Bcube + Ccube =3abc

here a = 11

b = 7

c = 4

Value is 3*(-11)*7*3

= 924