Without actually calculating the cubes , find the value of (-12)³ + (8)³ + (4)³
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Here a^3+b^3+c^3 formula will be used where a+b+c=0
a^3+b^3+c^3=3abc where a+b+c=0
(-12)^3+(8)^3+(4)^3= 3(-12)*8*4 where -12+8+4=0
Answer= -1152
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a^3+b^3+c^3=3abc where a+b+c=0
(-12)^3+(8)^3+(4)^3= 3(-12)*8*4 where -12+8+4=0
Answer= -1152
Mark me the brainliest
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