Question

without actually calculating the cubes,find the value of: (-3/4)^3 + (-5/8)^3 + (11/8)^3

Answer 1

by using identity : a³+b³+c³ = 3abc
putting value : 3*(-3/4)*(-5/8)*(11/8)
                      = 495/256
                     

Answer 2

by using the identity : a^3 +b^3 + c^3 = 3 abc
putting values :
3×(-3/4)×(-5/8)×(11/8)
...now..
= 495/256...
therefore the answer is 495/256
......
hope it helps you ....