without actually calculating the cubes,find the value of: (-3/4)^3 + (-5/8)^3 + (11/8)^3
Answers
Answered by
74
by using identity : a³+b³+c³ = 3abc
putting value : 3*(-3/4)*(-5/8)*(11/8)
= 495/256
putting value : 3*(-3/4)*(-5/8)*(11/8)
= 495/256
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Answered by
35
by using the identity : a^3 +b^3 + c^3 = 3 abc
putting values :
3×(-3/4)×(-5/8)×(11/8)
...now..
= 495/256...
therefore the answer is 495/256
......
hope it helps you ....
putting values :
3×(-3/4)×(-5/8)×(11/8)
...now..
= 495/256...
therefore the answer is 495/256
......
hope it helps you ....
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