Without actually calculating the cubes, find the value of (-32)3
+ (18)3
+ (14)3
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We know that
If (x+y+z= 0)
Then
X^3+y^3+z^3=3xyz
-32 + 18 + 14 = 0
So
(-32) ^3 + (18)^3+ (14)^3= 3(x)(y)(z)
=> 3(-32)(18)(14)
=24192
If (x+y+z= 0)
Then
X^3+y^3+z^3=3xyz
-32 + 18 + 14 = 0
So
(-32) ^3 + (18)^3+ (14)^3= 3(x)(y)(z)
=> 3(-32)(18)(14)
=24192
lakshaygenius:
is this right
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