Question

without actually calculating the cubes, find the value of 48^3 - 30^3 - 18^3
please tell the answer

Answer 1

$(48) {}^{3} + ( - 30) {}^{3} + (18) {}^{3}$
We know that,
if a+b+c=0
or, 48-30-18=0
then
$a {}^{3} + {b}^{3} + c {}^{3} = 3abc$
Let a=48. b= -30. c= -18
•°•3abc=3*48*-30*-18
=77760

----------Hope this will be helpful.

Answer 2

let a=48, b= -30 and c= -18
Now a+b+c= 0 (49-30-18)=0
since a+b+c=0 then,
a3+b3+c3=3abc
(48)3 +(-30)3 +(-18)3. =
3(48-30-18) =
3(48) (-30) (-18)= 77760

hope it helps you!