Question

without actually calculating write the quotient when sum of 3 digit number abc and number obtained by interchanging the digit cyclically i.e bca and cab is divided by
a.111. b. (a+b+c). c.37. d.3​

Answer 1

Answer:

Step-by-step explanation:

Let the digits of the number be a, b and c taken in order.

i.e 100a+10b+c        (original number)    .....(1)

1 cyclic rotation will give:  100b + 10c + a    .....(2)  

2nd cyclic rotation will give:  100c + 10a + b    .....(3)  

sum of (1), (2) and (3) will give: (100a + 10b + c)+(​ 100b + 10c + a)+(100c + 10a + b ) =111a+111b+111c

on dividing 111a+111b+111c with 111 we will get: a+b+c

Hence, quotient is ​ a+b+c.