without actually finding the cubes find the value of (0.2)^3-(0.3)^3+(0.1)^3
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a³+b³+c³-3abc
a³+b³+c³=3abc
so, 3(0.2×(-0.3)×0.1)
⇒ 3(-0.006)
⇒-0.018
a³+b³+c³=3abc
so, 3(0.2×(-0.3)×0.1)
⇒ 3(-0.006)
⇒-0.018
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