Question

Without actually finding the cubes , Find the value of : (75)^3+(-40)^3+(-35)^3

Answer 1

use the formula

a^3+b^3+c^3 =

(a+b+c)(a^3+b^3+c^3)+3abc

hence put the values of a b and c in this given formula u will get the answer...

Plzz mark me brainlist....

Answer 2

✍✍✍✍✍ ANSWER ✍✍✍✍✍✍✍

$think \: that \\ {75}^{3} = {a}^{3} \\ {( - 40)}^{3} = {b}^{3} \\ {( - 35)}^{3} = {c}^{3} \\ we \: know \: that \\ {a}^{3} + {b}^{3} + {c}^{3} - 3abc = 0 \\ {a}^{3} + {b}^{3} + {c}^{3} = 3abc \\ so \\ {75}^{3} + { (- 40)}^{3} + {( - 35)}^{3} \\ = > 3 \times 75 \times ( - 40) \times ( - 35) \\ = > 315000$

31500 is your answer ✔✔✔✔

✨✨hope it helps✨✨