Without actually multiplying calculate the cubes (-12)3+(8)3+(6)3
SmridhiBhadra:
instead of 6 it should be 4 i think
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a3+b3+c3=3abc
= 3×-12×8×6
=-1728
hope it helps
pls mark as brainlist.
hey a+b+c is not equal to zero. -12+14=2. so you can't use the formula
it has been taught by our teacher
Answered by
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x+y+z=-12+8+6
=-12+14
=-2
x3+y3+z3=3xyz
=3 (-12)(8)(6)
=-1728
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