Without actually performing long division state whether 129 ÷ 2 ^2 × 5 ^ 7 × 7 ^ 5
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is ur question complete i think it is complete der should be some question after those numbers
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To have an terminating decimal expansion the denominator must have only 2 and 5 as its factors in the simlified form of fraction for any degree or power of 2 and 5
denominator = 2^2 × 5^7 × 7^5
Since it have 7 also in its prime factors. Thus it doesn't have an terminating decimal expansion.
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denominator = 2^2 × 5^7 × 7^5
Since it have 7 also in its prime factors. Thus it doesn't have an terminating decimal expansion.
Plzz mark as brainliest
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