Without actually performing the long division state whether the following rational numbers will have a
terminating decimal expansion or a non-terminating repeating decimal expansion
(a)
13/
3132 (b) 64/455
Answers
Answered by
37
(a) 13/3132
Factorize the denominator we get
3132 =2×2×3×3×3×29 = 2^2×3^3×29
There are 2, 3 and 29 also in denominator so denominator is not in form of 2^n*5^m . Hence 13/3132 is not terminating.
(b) 64/455
Factorize the denominator we get
455 =5 x 7 x 13
There are 7 and 13 also in denominator so denominator is not in form of 2^n*5^m . hence 64/455 is not terminating.
Factorize the denominator we get
3132 =2×2×3×3×3×29 = 2^2×3^3×29
There are 2, 3 and 29 also in denominator so denominator is not in form of 2^n*5^m . Hence 13/3132 is not terminating.
(b) 64/455
Factorize the denominator we get
455 =5 x 7 x 13
There are 7 and 13 also in denominator so denominator is not in form of 2^n*5^m . hence 64/455 is not terminating.
paritoshvatsa:
btw its not 3125 its 3132
Answered by
4
Step-by-step explanation:
(a).13/3132
factorize denominate we her
3132=2×2×3×3×3×29=2^2×3^3×29
therefore.the are 2,3,29 also in decimal so denominator is not in this term of 2^n×5^n.
Hence 13/3132 is not terminating.
(b).64/455
Factor the denominator we het
455=5×7×13.
therefore are 7 and 13 also decimal so denominators is not in this termof 2^n×5^n
Hence 64/455 is not terminating
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