Math, asked by umikarlo75, 8 months ago

without actually performing the long division state whether 13|3125 and 13|343 will have terminating decimal expansion or non.terminating repeating decimal expansion???? guys fast...!​

Answers

Answered by mathdude500
27
If denominator can be factorised in the form of 2 ^m 5^n then its decimal expansion is terminating otherwise non terminating.

(i) 3125 can be factorised as 5^5
It means 13/3125 have terminating decimal expansion

(ii) 343 can be factorised as 7^3
It means 13/343 is non terminating
Answered by pulakmath007
3

SOLUTION

TO CHECK

To identify the below two fractions have terminating decimal expansion or a non - terminating repeating decimal decimal expansion

 \displaystyle \sf{ (i) \: \: \: \frac{13}{3125} \: \: }

 \displaystyle \sf{ (ii) \: \: \: \frac{13}{343} \: \: }

CONCEPT TO BE IMPLEMENTED

 \displaystyle \sf{\: Fraction \: = \: \frac{Numerator}{Denominator} \: }

A fraction is said to have terminating decimal expansion if the 2 & 5 are the only prime factors of the denominator

Otherwise the fraction is said to have non terminating decimal expansion

EVALUATION

CHECKING FOR OPTION (i)

 \displaystyle \sf{ (i) \: \: \: \frac{13}{3125} \: \: }

Here denominator = 3125

Now

 \sf{ 3125 = 5 \times 5 \times 5 \times 5 \times 5\: \: }

Since 5 is the only prime number present in prime factorisation of 3125

Hence this fraction has terminating decimal expansion

CHECKING FOR OPTION (ii)

 \displaystyle \sf{ (ii) \: \: \: \frac{13}{343} \: \: }

Here denominator = 343

Now  \sf{ 343 = 7 \times 7 \times 7\: }

Since 7 is the prime number present in prime factorisation of 343

Hence this fraction has non terminating decimal expansion

RESULT

 \boxed{ \displaystyle \sf{ (i) \: \frac{13}{3125} \: \: has \: terminating \: decimal \: expansion \: }}

 \boxed{ \displaystyle \sf{ (ii) \: \frac{13}{343} \: \: has \:non \: terminating \: decimal \: expansion \: }}

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