Question

Without adding, find the sum

(i)1+3+5+7+9
(ii)1+3+5+7+9×11+13+15+17+19
(iii)1+3+5+7+9+11+13+15+17+19+21+23​

Answer 1

Answer:

(1) 25. (2). 159 (3). 138

Answer 2

Answer:

Hey mate ✌️✌️

Step-by-step explanation:

(I)Total consecutive odd numbers = 5

Thus, n = 5

Therefore, sum =

${5}^{2}$

sum = 25

(ii) Total consecutive odd numbers = 10

Thus n = 10

$therefore \: sum \: = {10}^{2}$

sum = 100

(iii) same as above

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