Question

Without addingfind the sum :
a..1+3+5+ 7 + 9 +11+13
b.. (I +3+5+7+9+ 11 +13 + 15 + 17+19)
c.. (1+3+5+7+9+11+13+15 + 17+19+21+23)​

Answer 1

Answer:

1.49

2.100

3.144

we can count the number of digits and square it.

Answer 2

Step-by-step explanation:

(a) 1+3+5+7+9+11+13=7^2=49

(a) 1+3+5+7+9+11+13=7^2=49(b)1+3+5+7+9+11+13+15+17+19=10^2=100

(a) 1+3+5+7+9+11+13=7^2=49(b)1+3+5+7+9+11+13+15+17+19=10^2=100(c)1+3+5+7+9+11+13+15+17+19+21+23=12^2=144

Hope it helps you.....

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