Question

Without building the graph, find the coordinates of the points of intersection of the graph of the equation (x+2)(y+3)=0 with the x- and y-axes.

Answer 1

Put x=0 ,

then y = -3 , this is the point (0,-3) of int. of curve with y axis

Put y=0

then x = -2 , this is the point (-2,0) of int. of curve with x axis

Answer 2

Concept introduction:

A point of intersection is the meeting point of two lines or curves. By graphing the curves on the same graph and finding their points of intersection, we can discover a point of junction graphically.

Given:

Here the equation that is given to is-

$(x+2)(y+3)=0$

To find:

We have to find the coordinates of the points of intersection of the graph of the equation.

Solution:

Put $x=0$ ,

then $y = -3$, this is the point $(0,-3)$ of int. of curve with $y$ axis.

Put $y=0$

then $x = -2$ , this is the point $(-2,0)$ of int. of curve with $x$ axis.

Final answer:

Hence, the final answer of the question is -

$(0,-3)$ and $(-2,0)$.

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