without calculating cube find the value of 14cube + 13cube +27cube
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x^3+y^3+z^3=3xyz
3*14*13*27
calculate it . the answer will cim
3*14*13*27
calculate it . the answer will cim
rajput7235:
thanks bro
Answered by
2
we have
if a+b+c=0 then a^3+b^3+c^3=3abc
let,
a=14 b=13 c=27
now
a+b+c=14+13+27
a+b+c=0
then a^3+b^3+c^3=3abc
=> a^3+b^3+c^3 = 3(1 4 ) ( 13) ( 27)
if a+b+c=0 then a^3+b^3+c^3=3abc
let,
a=14 b=13 c=27
now
a+b+c=14+13+27
a+b+c=0
then a^3+b^3+c^3=3abc
=> a^3+b^3+c^3 = 3(1 4 ) ( 13) ( 27)
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