Without drawing the graph, show that y = 5x - 3y = 4 - 2x and 2x - 3y = 8 are concurrent lines
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Step-by-step explanation:
y=5x-3y=4-2x
On solving we get,
7x-4y=4____(i)
2x-3y=8____(ii)
a=7,b=-4, c=4
a'=2,b'=-3,c'=8
a/a'=7/2
b/b'= -4/-3=4/3
c/c'=4/8=1/2
As we know that If the line is concurrent or intersecting at one point then it will,
(a/a' is not equal to b/b')
therefore, 7/2 is not equal to 4/3
So the line will concurrent and intersect and one point
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