without expanding prove that
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using completing square method
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Solution:
= (x + y)(x - y) + (y + z)(z - y) + (z + x)(z - x)
= x² - y² + y² - z² + z² - x² ------------------------- (∵ a² - b² = (a + b)(a - b))
= 0
Step-by-step explanation:
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