Without finding the cubes , factorise (2x-5y)3+(5y-3z)3+(3z-2x)3.
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Answered by
55
See the pic.
Hope it helps and Mark me brainliest if pleased.
Hope it helps and Mark me brainliest if pleased.
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Answered by
8
Step-by-step explanation:
We know that a^3 + b^3 + c^3 = 3abc if a + b + c =0
Here a + b + c = 2x - 5y - 3z - 2x + 5y + 3z = 0
Therefore the sum of their cubes is 3(2x - 5y)(5y - 3z)(3z - 2x)
Hope this helps.....
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