without finding the cubes factorise (x-2y)³+(2y-3z)³+(3z-x)³
step wise step solution best answer I will mark as brainlist
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Answer:
3(x-2y)(2y-3z)(3z-x)
Step-by-step explanation:
(refer attachment)
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According to me the answer would be
As there is an identity
(a-b)^3+(b-c )^3+(c-a)^3=3(a-b)(b-c)(c-a)
So answer would be
3(x-2y)(2y-3z)(3z-x)
Pls mark it as the brainliest answer
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