Math, asked by Pranavbindal31, 8 months ago

Without finding the cubes multiply (x-y)^3 + (y-z)^3 + (z-x)^3

Answers

Answered by pallavisami
0

Answer:

When  a+b+c = 0  we know that  a³ + b³ + c³ =  3 a b c

(x-y)³ + (y-z)³ + (z - x)³

     = 3 (x - y) (y -z) (z- x)

     = 3 (xy - x z -y² + yz) (z -x)

     = 3 (xyz - x² y - x z² + x² z - y² z + x y² + y z² - xyz)

     = 3 [ x² (z - y) + z² (y - x)  + y² (x - z)

HOPE THIS HELPS YOU

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Answered by Lueenu22
0

Step-by-step explanation:

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