Question

Without finding the zeroes alpha and beta of the polynomial p(x) = x^2 - 5x + 6, find the values of following 1/alpha + 1/beta

Answer 1

Answer:

$\huge\bold\red{Answer}$

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Given:-

• $\bold{p(x)=x^2-5x+6}$
• $\bold\alpha$ and $\beta$ are the zeroes of p(x)

To find:-

• $\bold \ value \ of \frac{1}{ \alpha }$ + $\frac{1}{ \beta }$

Solution:-

$\bold{Given,p(x)=x^2-5x+6}$

$\bold \ Here \ \alpha + \beta =-b/a$

$\bold{=-(-5)/1}$

$\bold{=5}$

$\bold \alpha × \beta =c/a$

$\bold{=6/1}$

$\bold{=6}$

$\bold \ now \frac{1}{ \alpha } + \frac{1}{ \beta }=\frac{ \ alpha + \ beta }{ \alpha \beta }$

$\bold=\mathsf{ \dfrac{5}{6}}$

⛬$\bold{VALUE\:OF\:THE\: EXPRESSION\:IS\:5/6}$

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$\huge\bold\green{Hope\:this\:help\:you}$

Answer 2

Answer:

5/6

Step-by-step explanation:

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