Question

Without using Pythagoras theorem, show that A (7, 10), B (-2, 5) and C (3,-4) are the vertices of a right angled triangle.

Answer 1

Please see the attachment

Answer 2

Answer:

Step-by-step explanation:

Without using Pythagoras theorem, show that A (7, 10), B (-2, 5) and C (3,-4) are the vertices of a right angled triangle.

Slope of AB = (5-10)/(-2-7) = -5/-9 = 5/9

Slope of BC = (-4 -5)/(3 -(-2)) = -9/5

Slope of AC = (-4-10)/(3-7) = -14/-4 = 7/2

Slope of AB * Slope of BC = (5/9)(-9/5) = -1

=> AB & BC are at right angle to each other

Hence ABC are the vertices of a right angled triangle