Question

without using table of value,draw the graph of y=x^2-4x+5​

Answer 1

Answer:

Step-by-step explanation:

y= ax² + bx + c

The x-coordinate of vertex and axis of symmetry of parabola is x = - $\frac{b}{2c}$

y = x² - 4x + 5

a = 1, b = - 4, c = 5

x = - (- 4) / 2×1 = 2

y = 2² - 4×2 + 5 = 1

Coordinates of vertex of parabola are (2, 1)

Now, to draw the parabola move the beginning of coordinates (0, 0) into point (2, 1) and draw the parabola y = x²