without using trigonometric tables evaluate 5 sin 28 degree sec 32 degree + tan 37 degree / cot 53 degree square + 16 square 36 degree minus cot square 54 degree it's also urgent please guys
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Step-by-step explanation:
Answer
sec
2
50
∘
−cot
2
40
∘
cos
2
20
∘
+cos
2
70
∘
+2csc
2
58
∘
−2cot58
∘
tan32
∘
−4tan13
∘
tan37
∘
tan45
∘
tan53
∘
tan77
∘
=
sec
2
50
∘
−tan
2
50
∘
cos
2
20
∘
+sin
2
20
∘
+2csc
2
58
∘
−2cot58
∘
cot58
∘
−4tan13
∘
cot13
∘
cot53
∘
tan53
∘
tan45
∘
=
1
1
+2csc
2
58
∘
−2cot58
∘
cot58
∘
−4×1×1×1
=1+2(csc
2
58
∘
−cot
2
58
∘
)−4
=1+2−4
=−1
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