Question

without using trigonometric tables evalute the expression 1. sec37/cosec53+2cot15×cot25×cot 45× cot75×cot65-3(sin^2 18+ sin^2 72​

Answer 1

sec37°/cosec53° + 2cot15° x cot 25 x cot 45 x cot 75 x cot65 - 3(sin^2 18 + sin^2 72)

= cosec(90-37)/cosec53 + 2cot(90-15) x cot 75 x 1 cot(90-25) x cot 65 - 3(cos^2 90-18) + sin^2 72)

= cosec 53/cosec 53 + 2cot75 x cot 75 x cot 65 x cot 65 - 3(cos^2 72 + sin^2 72)

= 1 + 2cot75 x 1/tan75 x cot65 x 1/tan65 - 3(1)

= 1 + 2 - 3

= 3 - 3

= 0

Answer 2

Step-by-step explanation:

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