Question

Without using trigonometric tables, prove:
sin2 28° - cos2 62° = 0​

Answer 1

here is your answer mate....

Answer 2

sin2 28°- cos2 62°=0

L.H.S

sin2 (90°-62°)- cos2 62°

sin2 62° - cos2 62°

0=R.H.S

Hence proved