Without using trigonometric tables, prove:
sin2 28° - cos2 62° = 0
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here is your answer mate....
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Answered by
7
sin2 28°- cos2 62°=0
L.H.S
sin2 (90°-62°)- cos2 62°
sin2 62° - cos2 62°
0=R.H.S
Hence proved
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