Math, asked by kiyoshi, 10 months ago

Without using trigonometric tables, prove:
sin2 28° - cos2 62° = 0

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Answered by taktushar8

7

here is your answer mate....

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Answered by tdydygu

7

sin2 28°- cos2 62°=0

L.H.S

sin2 (90°-62°)- cos2 62°

sin2 62° - cos2 62°

0=R.H.S

Hence proved

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