Wjat should be the least value that must be assigned to # so that the number 564811# is exacyly divisible by 9
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Step-by-step explanation:
The remainder when a number is divided by 9 is the same as for the sum of the digits of that number.
So this number is exactly divisible by 9 only if the sum of its digits is divisible by 9.
5 + 6 + 4 + 8 + 1 + 1 + #
= 25 + #
To make this divisible by 9, we need # to be 2. Then the sum of the digits would be 27 = 3 × 9, and therefore the original number will be divisible by 9.
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