Math, asked by Buddhadev6719, 1 year ago

Wjat should be the least value that must be assigned to # so that the number 564811# is exacyly divisible by 9

Answers

Answered by Anonymous
2

Answer:

2

Step-by-step explanation:

The remainder when a number is divided by 9 is the same as for the sum of the digits of that number.

So this number is exactly divisible by 9 only if the sum of its digits is divisible by 9.

5 + 6 + 4 + 8 + 1 + 1 + #

= 25 + #

To make this divisible by 9, we need # to be 2.  Then the sum of the digits would be 27 = 3 × 9, and therefore the original number will be divisible by 9.


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