Wo vectors a and b of magnitude 3 units and 4 units respectively make an angle 60 degree with each other. a) find the magnitude and the direction of the resultant vector.
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Two vectors A and B of magnitude 3 units and 4 units are inclined at angle 60°.
We have to find magnitude and direction of the resultant vector
★ By parallelogram law of vector addition, the magnitude of resultant R at two vectors A and B inclined to each other at angle θ, is given by
- R² = A² + B² + 2AB cosθ
By substituting the given values,
➝ R² = 3² + 4² + 2(3)(4)cos60°
➝ R² = 25 + (24 × √3/2)
➝ R² = 25 + 12√3
➝ R² = 45.76
➝ R = 6.76 N
Direction of the resultant vector :
If resultant R makes an angle β with A then
- tan β = Bsinθ/(A + Bcosθ)
➝ tan β = 4sin60°/(3 + 4cos60°)
➝ tan β = (4√3/2)/(3 + 4/2)
➝ tan β = 2√3/(3+2)
➝ tan β = 2√3/5
➝ tan β = 0.692
➝ β = 34.68°
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