Question

womens on is two years older than her daughter her age is three times the sum of the ages of her children after 5 years he will be 47 years old find the present ages of the children ???​

Answer 1

solution:-

=> The present age of the woman is

47 - 5 = 42.

=> Since the woman's age is 3 times the sum of the ages of the children,

this sum is 42/3 = 14.

=> So for children ages you have two equations:

=>s + d = 14,

=>s - d = 2.

=> Every time when you see two equations like these, add them.

You will get

=>2s = 14 + 2,

=>2s = 16,

=>s = 16/2 = 8.

Thus son is 8 years now.

The daughter is 8 - 2 = 6 years.

i hope it helps you.