Question

wooden slab starting from rest slides down an inclined plane of length 10 M with an acceleration of 5 m/s square what would be its speed at the bottom of the inclined plane

Answer 1

answer is 10m/sec

we use the third equation of Newton

Answer 2

Wooden slab starts sliding down from rest

So that intial velocity u= 0

The length of the inclined plane is 10m

So s=10

It's acceleration is 5m/s²

So a=5m/S2

We need to find the final velocity i.e v

Using the equation of motion

V²-U²=2as

v²-0² = 2*5*10

v² =100

v=√100


so v is 10

This final velocity of the wooden slab is 10m/s.

Hope this helps you friend
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