Physics, asked by shrutikabelkhede123, 6 months ago

Work
17
The angular momentum of a particle about point ois L=rx mv. Here, r =OP A particle
of mass 2 kg moving with velocity v = (-i + k) ms. At some instant it is located at point
9-p(43. 5)m. Find its angular momentum about O (1, 2, 3)m.
UR
P
O
a (6+2ị + 8k) kg-m's-1
c. (-6î - 2- 8k) kg-ms-
b. (6 + 2ſ - 8k) kg-ms-1
d. (6-2- 8k) kg-ms​

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Answered by binadevi1983bablu
0

Answer:

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