Question

Work done by restoring force in a wire within elastic limit is -10j maximum amount of heat produced ?

Answer 1

As per thermodynamics law, $\Delta Q=\Delta U+\Delta W$

where $\Delta Q heat energy absorbed/released, [tex]\Delta U is changed in internal energy and [tex]\Delta W is work done.</p><p>Restoring force acts so quickly, there will be negligible heat loss. Hence we approximate this process as adiabatic and \Delta Q = 0</p><p>Hence we have, [tex]\Delta U+\Delta W=0$, since \Delta W = -10 J, we have \Delta U = 10 J.

Answer 2

Answer: 10 J

Explanation:

The maximum amount of heat produced would be when the entire work done is converted into heat.

It is given that work done by restoring force in a wire with elastic limit is -10 J

Thus,

Maximum Heat produced = Total Work done = 10 J