Question

Work done in blowing a soap bubble of
diameter 2 cm, is (S.T. = 3 × 0.001N/m)
​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

Work done in blowing a soap bubble of diameter 2 cm, is (S.T. = 3 × 0.001N/m)

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$\large\underline{\underline{\sf Given:}}$

• Surface Tension(T) = 3 × 0.001 N/m
• Diameter of soap bubble = 2cm or ${\sf 2×10^{-2}m}$

$\large\underline{\underline{\sf To\:Find:}}$

• Work done

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$\implies{\sf r_1=0 }$

$\implies{\sf r_2=1×10^{-2}m }$

✪$\large{\boxed{\bf \blue{Work\:Done=T×8π(r_2-r_1)}}}$

$\implies{\sf W = 3×10^{-3}×8×3.14(1×10^{-3}-0) }$

$\implies{\sf W = 75.35×10^{-6}}$

$\implies{\bf \red{Work\:Done(W)=7.53×10^{-5}J} }$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Work done in blowing a soap bubble of

diameter 2 cm is ${\bf \red{7.53×10^{-5}J}}$.