Physics, asked by nandhavishavdee6659, 1 year ago

Work done in blowing liquid soap bubble of radius r having surface tension t is

Answers

Answered by Pakhi44
0
\huge{\bold{Heya..!!}}



We know that a bubble has two surfaces in contact with air, so the total surface area of the bubble will be
=2×(4πR2)=8πR2Now, work done=Surface tension × Increase in surface area=T×(8πR2−0)=8πR2T


Thanks.... :)
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