Work done in converting 1g of ice at -10 C to steam at 100C is
Answers
Answer:
i think 0 degree celcius
Answer:
When calculating heat energy, you need to use the equation: q=mc(ΔT) where q is heat energy, m is mass, c is specific heat and ΔT is the change in temperature. In this case, the total energy is the sum of the energy it takes to heat the ice to 0° (1), melt the 0 ice to 0° water (2), the energy it takes to heat to water to 100° (3), the energy to convert 100° water to 100° steam (4), and the energy is takes to get to 127.5° steam (5). For steps 2 and 4, there is energy for the phase changes which are calculated by a different equation: q=mΔHf where Hf is heat of fusion. Taking all of this into account you get:
(1)
q=(97.5g)(2.09J/g*°C)(0°C-(-46.5°C))= 9,475.53 J
(2)
q=(97.5g)(334J/g)= 32565 J
(3)
q=(97.5g)(4.18J/g*°C)(100°C-0°C)= 40755 J
(4)
q=(97.5g)(2257J/g)= 220,057.5 J
(5)
q=(97.5g)(2.09J/g*°C)(127.5°C-100°C)= 5,603.81
TOTAL: 308,456.84 J
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