Question

Work done in increasing the potential difference of a capacitor from 4v to 6v is w

Answer 1

We know that ,
Potential difference = Work done/ time

So, When V is increased from 4 v to 6v

The Work done also increased.

Therefore Work done will be 6 joule

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Answer 2

Answer:

The work done is same.

Explanation:

Suppose that, the work done in increasing the P.D across the plates of a capacitor from 4 V to 6 V is w. The further work done in increasing the P.D from 6 V to 8 V is

We need to calculate the work done

Using formula of work done

$w=q\times V$

Put the value into the formula

$w=q\times(6-4)=2q$

$q=\dfrac{w}{2}$

We need to calculate The further work done in increasing the P.D from 6 V to 8 V

Using formula of work done again

$w'=q(8-6)=2q$

Put the value of q from equation (I)

$w'=\dfrac{w}{2}\times2$

$w'=w$

Hence, The work done is same.