Work done in moving 5ccof charge across the ends of the conductor is 100 J. If the potential at the one end of the conductor is 10 very find the potential at other end of the conductor
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W12=Q(V2-V1),where V2=10v,V1=?
100=5(10-V1)
V1=-10
100=5(10-V1)
V1=-10
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