Question

Work done in the cyclic process shown in figure is
PA
3P.
PO
V.
• V
3V.
(2) 4P.V.
(0,0)
(1) 4P.V.
22
(3) EPVO
7
(4) -13P.V.​

Answer 1

Explanation:

As we linow that area under p−v Curve gives worle done. as we know that area of circle is given as =πr2 but kere The que of curve is given as

A=πr1γ2

Where γ1=3v0−V02=2v0v2

γ1=v0

γ2=3p0−P02=P0 γ1=v0;r2=p0 Work done =−πγ1Y2abecouse circle 15 anticlockwise

=−πv0p0πv0p0{π=227}

Work =−227 povo Aus0,7+π/3