work of 5 Joules is done in stretching a spring from its natural length to 10cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (10 cm) ?
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work = force * displacement
5 = f * 0.1
5 / 0.1 = f
therefore
f = 50 N
i hope it helps.....
5 = f * 0.1
5 / 0.1 = f
therefore
f = 50 N
i hope it helps.....
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