Question

work of 6.0×10^-4 joule is required to be done in increasing the size of soap film from 10cm×6cm to 10cm×11cm.what is the surface tension of the film​

Answer 1

The answer is 3x10^-2 N/m
Solution:

Surface tension(s)
S=work done/increase area
S=6.0*10^-4/2(10*11-10*6) 10^-4 m^2
S=1.5*10^-6

MARK BRAINLIEST

Answer 2

Explanation:

by using the formula

w is T*A1-A2

THEN ANSWER IS

6*10POWER OF -2