Question

Work out 2 1/7 + 1 2/5

Answer 1

Answer:

95/28

Step-by-step explanation:

It is important to notice that this is the addition of two mixed fractions which firstly needs to be changed into improper fractions. Take 2 1/7 - first multiply the denominator by the whole number to give 14 and now add the numerator to this number to get 15 - the fraction in improper form is 15/7. Do the same process with 1 1/4 - so 4 x 1 = 4 and now 4 + 1 = 5 - the new fraction is 5/4. We now have to add the two improper fractions together. To do this we need the denominator to be the same in both fractions. We find the lowest common multiple of 4 and 7 which is simply 28. For 15/7 we multiply the top and bottom of the fraction by 4 to give 60/28 and for 5/4 we multiply the top and bottom of the fraction by 7 to give 35/28 Finally we can add the two fractions together by keeping the denominator as 28 and simply adding the two numerators together to give 95/28. This number cannot be simplified further.

Answer 2

Answer:

Required answer is $3 \frac{19}{35}$

Step-by-step explanation:

Given,

$2 \frac{1}{7} + 1 \frac{2}{5}$

We want to simplify it.

$\frac{2 \times 7 + 1}{7} + \frac{1 \times 5 + 2}{5} \\ = \frac{14 + 1}{7} + \frac{5 + 2}{5} \\ = \frac{15}{7} + \frac{7}{5} \\ = \frac{15 \times 5 + 7 \times 7}{35} \\ = \frac{75 + 49}{35} \\ = \frac{124}{35} \\ = 3 \frac{19}{35}$

This is a problem of Fraction.

Fraction is a major part of Algebra.

Some important Algebra's formula:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Algebra's problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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