Worker a takes 8 hours to do a job. Worker b takes 10 hours to do a job. How long should it take both a and b, working together to do same job.
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Answered by
1
Answer:
Step-by-step explanation:
A does in 8 hours. Hence, he does 1/8 part of job in 1 hour.
Similarly, B does 1/10 of job in 1 hour.
When they will work together on same job, they will do [(1/8)+(1/10)] of the job in one hour.
1/8+1/10⇒ (5+4)/40
⇒ 9/40
They do 9/40 of job in 1 hour.
So, they do the job in 40/9 days. {40/9 days= 4.4 days or 4 days and 6 hours)
Hope it helps you....
Answered by
4
Answer
One hour work of:
A = 1/8
B = 1/10
1/A + 1/B = 1/8 + 1/10
= 18/80
= 9/40
A + B = 40/9 = 4.45 hours
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