Question

Working together Andy and Angela can complete a work in 6 days. Working individually Andy can
complete the same work in 10 days. What time can Angela take to complete the work alone?​

Answer 1

Answer:

Andy and Angela together in 6 days

Andy alone can do in 10 days

lcm of 6,10 is 30

Andy and angela can do 5 piece of work per day

Andy alone can do 3 piece of work per day

5-3 is 2 that would be the anglea piece of work

so..30/2 is 15 days

15 days ..is the correct ans

Answer 2

Angela can take 15 days to complete the work alone.

Step-by-step explanation:

• Andy and Angela can complete the task in 6 days when working together. So, in a day, they will be able to complete $\frac{1}{6}^{th}$ part of the task.

Therefore, (Andy + Angela)'s one day work will be equal to $\frac{1}{6}$

• Similarly, if Andy alone can take 10 days to complete the work then Andy's one day work would be: $\frac{1}{10}$

Therefore, Angela's one-day work: $\frac{1}{6}-\frac{1}{10}$ (taking lcm of 6 and 10, we get 30 as an answer).

⇒ $\frac{(5-3)}{30}=\frac{2}{30}$

∴ $\frac{1}{15}$

Hence, in one-day Angela completes the $\frac{1}{15}^{th}$part of the work so she will complete the entire work in 15 days.