Math, asked by jayvadivel, 9 months ago


Working together, Rajeev and Vikram can complete a piece of work
in 48 days. Rajeev can complete the work alone in 64 days. Both of
them worked together for 30 days and then Rajeev left. How long will us
Vikram take to complete the remaining work? GRS​

Answers

Answered by mridumoloy
23

Answer:

72 days

Step-by-step explanation:

This problem can be done using lcm concept

quantity of work to be done=lcm(64,48)=192units

work done by rajeev and vikram=192/48=4units/day

work done by rajeev =192/64=3units/day

so work done by vikram=4-3=1units/day

work done by rajjev and vikram in 30 days=30*4=120units

Remaining work to be done by vikram=12-120=72units

so time taken by vikram to complete 72 units=72/1=72days

Answered by rishika79
12

Answer:

Step-by-step explanation:

72 days

If Vikram alone can complete the work in 'x' days, then their 1 day work=(1/64)+(1/x)=1/48

1/x=(1/48) -(1/64)=1/92

So 30 days work of Rajeev & Vikram=30*(1/48)=5/8, Remaining work=3/8

Days required for Vikram to complete remaining work=(3/8)/(1/192)=72

Hope it helps you....

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